Rearange to find x in terms of y and t, in simplest form. (assume [math]y+3t\neq0[/math])

 

[math]y(y-x)=3t(3t+x)[/math]

 

I have

 

[math]x=\frac{9t^2-y^2}{3t+y}[/math]

 

Is this the simplest form?

No, the term can be simplified. Your result is not correct, either (sign error).

Rearange to find x in terms of y and t, in simplest form. (assume [math]y+3t\neq0[/math])

 

[math]y(y-x)=3t(3t+x)[/math]

 

I have

 

[math]x=\frac{9t^2-y^2}{3t+y}[/math]

 

Is this the simplest form?

 

You'll need to make use of the difference of perfect squares in the numerator. Although, you do have a sign error. Btw, show your work.

 

[hide]I got x=y-3t[/hide]