ghostunitt Posted November 11, 2006 Share Posted November 11, 2006 I have a trig project due on Tuesday and I have no idea how to solve it. (I have an idea but want to make sure I'm right) The problem goes as follows: An artist is creating triangular ceramic tiles for a triangular patio. The patio will be an equilateral triangle with base 18ft and height 15.6 ft. a. Find the area b. The artist uses tiles that are isosceles triangles with base 6 in. The function y=3 tan O (O means Theta...) models the height of the tiles, where O is the measure of one of the base angles. Graph the function. Find the height of the tile when O=30degrees and when O=60degrees c. Find the area of one tile in square inches when O=30 degrees and 60 degrees d. Find the number of tiles the patio will require if )=30 or 60 degrees Please help me as soon as possible answers and solutions Thank you... Link to comment Share on other sites More sharing options...
insane_alien Posted November 11, 2006 Share Posted November 11, 2006 and your not going to tell us the idea you had so we can tell you if our right or wrong? dude, we are NOT here to do your homework for you. Link to comment Share on other sites More sharing options...
D H Posted November 11, 2006 Share Posted November 11, 2006 and your not going to tell us the idea you had so we can tell you if our right or wrong? His idea was that someone on this forum would do his homework for him. It looks like he has the wrong idea. Link to comment Share on other sites More sharing options...
insane_alien Posted November 11, 2006 Share Posted November 11, 2006 oh i will help him, he just won't get it done for him. Link to comment Share on other sites More sharing options...
Bignose Posted November 11, 2006 Share Posted November 11, 2006 The patio will be an equilateral triangle with base 18ft and height 15.6 ft. Here is the very first problem, ghostunitt, go back and review the definition of an equilateral triangle. Link to comment Share on other sites More sharing options...
uncool Posted November 11, 2006 Share Posted November 11, 2006 Here is the very first problem, ghostunitt, go back and review the definition of an equilateral triangle. Actually, this is correct - the height of an equilateral triangle with 18 feet-long sides is about 15.6. =Uncool- Link to comment Share on other sites More sharing options...
Phi for All Posted November 11, 2006 Share Posted November 11, 2006 ghostunitt, I have moved your thread to the proper forum, where people will know you need help and not answers. I have an idea but want to make sure I'm rightPlease share this idea, it will help our members see how far along you are and how best to help. Posting here in Homework Help will make the hecklers go away as well. Link to comment Share on other sites More sharing options...
Bignose Posted November 12, 2006 Share Posted November 12, 2006 My bad, I misinterpreted what you meant. I misread it since it is unnecessary to say what the height would be, an "equilateral triangle with side of 18" completely defines the situation. That said, show us what work you have done, and we will do our best to verify its accuracy. We are not going to post our solution just for you to check at home, because, frankly, we cannot just take your word that you have done the work yourself. Link to comment Share on other sites More sharing options...
ghostunitt Posted November 12, 2006 Author Share Posted November 12, 2006 Ok well part a is obvious I got 1/2 base X height gives area....part B is simple too...I just plugged the given numbers for theta ( the 'O') thing....now part c is one part that I do not understand....Well I will have the height after using the equation y=3tan O....but where do I find how large the base is so I can find area? Link to comment Share on other sites More sharing options...
ghostunitt Posted November 12, 2006 Author Share Posted November 12, 2006 wow im dumb...(base 6 in written in quesstion) I'd just like to say thanks to the assholes ...yes thank you....for making me try myself...easier then I thought Link to comment Share on other sites More sharing options...
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