encipher Posted October 24, 2006 Share Posted October 24, 2006 How would you figure out if this converges or diverges: 1/((n)(lnn)^2) Link to comment Share on other sites More sharing options...
Klaynos Posted October 24, 2006 Share Posted October 24, 2006 There are a few methods I belive. One of which is the Newton–Raphson method. I recall (from several years ago) that this is the most mathematically heavy but most likely to work method... http://en.wikipedia.org/wiki/Newton's_method Have fun. Link to comment Share on other sites More sharing options...
Dave Posted October 24, 2006 Share Posted October 24, 2006 I'm going to assume that you mean the sequence: [math](a_n)_{n=1}^{\infty} = \frac{1}{n \log^2 n}[/math] instead of the continuous function. But the same principle should apply, I think. You should notice that, for [imath]n \geq 2[/imath], [imath]0 \leq \frac{1}{n} \leq 1[/imath]. So, [math]0 \leq \frac{1}{n \log^2 n} \leq \frac{1}{\log^2 n}[/math] The rest should be obvious. Link to comment Share on other sites More sharing options...
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