caseclosed Posted March 17, 2006 Share Posted March 17, 2006 this problem, I don't even have a clue where to start... Link to comment Share on other sites More sharing options...
Tartaglia Posted March 17, 2006 Share Posted March 17, 2006 Substitute sinx = 2t/(1+t^2) cosx = (1-t^2)/(1+t^2) where t = tan(x/2), dt/dx = 1/2*(1+t^2) rearranging gives / | dt/(1+t) = ln(1 + tan(x/2)) + c / Link to comment Share on other sites More sharing options...
NeonBlack Posted March 17, 2006 Share Posted March 17, 2006 This one is kind of a mess. Try integration by parts. Let [math]dv=dx[/math] [math]u=\frac{1}{1+cosx+sinx}[/math] Do that process, then you'll have to do integration by parts again. Have fun. Edit: Nevermind! This just brings you in circles. Tartaglia's is probably better. Link to comment Share on other sites More sharing options...
caseclosed Posted March 17, 2006 Author Share Posted March 17, 2006 Substitute sinx = 2t/(1+t^2) cosx = (1-t^2)/(1+t^2) where t = tan(x/2)' date=' dt/dx = 1/2*(1+t^2) rearranging gives / | dt/(1+t) = ln(1 + tan(x/2)) + c /[/quote'] I got the answer / | ln(2 + 2tan(x/2)) + c / after looking up my identity sheet and I saw those substitutions but for dt/dx it is (2dt) / (1+t^2) which is different from your 1/2*(1+t^2). Link to comment Share on other sites More sharing options...
Tartaglia Posted March 17, 2006 Share Posted March 17, 2006 Your expression is for dx not dt/dx and so it is tha same as mine only upside down. You are also obviously unfamiliar with the laws of logs as ln(2 + 2tan(x/2)) = ln2 + ln(1+tan(x/2)) and the ln2 disappears into the integration constant Link to comment Share on other sites More sharing options...
caseclosed Posted March 17, 2006 Author Share Posted March 17, 2006 Your expression is for dx not dt/dx and so it is tha same as mine only upside down. You are also obviously unfamiliar with the laws of logs as ln(2 + 2tan(x/2)) = ln2 + ln(1+tan(x/2)) and the ln2 disappears into the integration constant ahh, you're right, I am not familiar with logs, heh. and o yeah that thing on my sheet is dx. lol. thanks!!! you're a genius at this, you got my vote Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now