ecoli Posted October 26, 2005 Share Posted October 26, 2005 For my chem lab, we have to do calculations based off Nerns's law. [math] E = E^{0} - \frac{RT}{F}ln [H^{+}] [/math] The question... From the Nernst equation as it applies to the pH electrode, calculate the difference in pH corresponding to a difference in voltage of 0.1 mV (0.0001 V) at 20 C Isn't this question missing information? such as E, since you need to solve for ln [H+]... am I right? Link to comment Share on other sites More sharing options...
tash =) Posted October 27, 2005 Share Posted October 27, 2005 I'm guessing, but wouldn't E be 0.1mV and E0 be zero? Link to comment Share on other sites More sharing options...
LazerFazer Posted October 27, 2005 Share Posted October 27, 2005 Couldn't it be re-arranged to read: [math] E - E^{0} = - \frac{RT}{F}ln [H^{+}] [/math] and since [math] \Delta E = E - E^{0} = 0.1mV [/math] you should be able to solve it. cheers, LF Link to comment Share on other sites More sharing options...
ecoli Posted October 29, 2005 Author Share Posted October 29, 2005 Couldn't it be re-arranged to read: [math] E - E^{0} = - \frac{RT}{F}ln [H^{+}] [/math] and since [math] \Delta E = E - E^{0} = 0.1mV [/math] you should be able to solve it. cheers' date=' LF[/quote'] yeah, that's it. I kinda figured that out after I posted this question, but thanks for the help anyways. The problem was, the lab that I got this equation from wasn't very clear on defining the variables. Thanks guys. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now