CPL.Luke Posted October 23, 2005 Share Posted October 23, 2005 so, I'm having a hard time with path independance, namely with how do you find the scalar function that your vector function is the gradient of. or G in (nabla)G = f Link to comment Share on other sites More sharing options...
swansont Posted October 23, 2005 Share Posted October 23, 2005 Integrate it Link to comment Share on other sites More sharing options...
CPL.Luke Posted October 25, 2005 Author Share Posted October 25, 2005 alright then I suppose my question lies more in what happens to the i's the j's and the k's when you integrate, for instance when you take the integral of f to get the scalar function G Link to comment Share on other sites More sharing options...
Tom Mattson Posted October 26, 2005 Share Posted October 26, 2005 alright then I suppose my question lies more in what happens to the i's the j's and the k's You leave them out of it. If [imath]\vec{\nabla}G=\vec{f}[/imath] then: [math]\frac{\partial G}{\partial x}=f_x[/math] [math]\frac{\partial G}{\partial y}=f_y[/math] [math]\frac{\partial G}{\partial y}=f_z[/math] Link to comment Share on other sites More sharing options...
CPL.Luke Posted October 27, 2005 Author Share Posted October 27, 2005 then in the end you just do fx+fy+fz correct? without an ij or k making it a scalar function. Link to comment Share on other sites More sharing options...
Tom Mattson Posted October 27, 2005 Share Posted October 27, 2005 No, in the end you have f(x,y,z). Link to comment Share on other sites More sharing options...
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