To answer the question posted by this user, this reaction proceeds through and SN1 mechanism because when the bromine atom leaves, it generates a highly stable benzylic carbocation. The positive charge on this intermediate is delocalized through the aromatic ring by resonance, which significantly stabilizes it. An SN2 mechanism would not be favorable in this case because the carbon bonded to bromine is statically hindered, preventing a nucleophile from attacking directly. Therefore, the reaction follows the SN1 mechanism.

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The question was answered. Many times. No need to answer it again.