Bohr sees electron as a sphere traveling on Bohr radius around proton (folowing“equator “ trajectory- in the middle between top “north”and

Bottom (south ) of proton .

In this revisited hydrogen model ,we are going to apply probability of finding electron graph (electron cloud ) to Bohr original model.

In this revisited model ,instead of one electron orbiting around proton

There is N electrons traveling one at a time from top side (north) of proton to the bottom side (south) of proton .

The direction of single electron  is perpendicular to original Bohr orbit .

The green spheres traveling north/ south (N/S) are trajectory of single electron traveling and “cutting “ the Bohr radius .Dots red ,blue ,green yellow are the pints where Bohr radius is “cut” by single electron .

The N number of electrons move N/S and their motion is synchronized to create  Bohr radius around proton.

The trajectory of single electron traveling north/south will

Follow probability function

The N number of electrons “cutting “the Bohr radius  is the

Number of electrons inside the electron cloud.

The radius of electron is Bohr circle

Circumference divided with N.

Let’s calculate number of electrons cutting the Bohr diameter in one second .

Bohr radius

Rb =5.29x10^-11m

Number of revolutions of single electron around proton

f=6.65x10^15/sec

Circumference of Bohr or or

C=5.44x10^-11m

The electro static force between electron and proton is

Fe=8.24x10^-8N

Impulse of electrostatic force

J=Fe x t

Fe =J/t

This force can be crated by a bunch of smaller J’ impulses .

Fe=N x J’ x t

Thus could be the reason for

The time  for single electron to travel

Distance C/2- from in N/S direction is

t’=0.15x10^-15 sec

J’=Fe x t’

J’=8.24x10^-8x0.15x10^-15

J’=1.236x10^-23

N’

Is the number of electrons traveling North / South in t’ time.

N’=J/J’

N’=8.24x20^-8/1.236x10^-23

N’=1.44x10^15

In one second

N=1.44x10^15***************

Single electron travels from North to South perpendicular to Bohr radius and cuts it .The electrons are synchronized and cut Bohr diameter one at a time (in average mode).

In real situation every single electron follows the spiral trajectory cording to probability graph.

In Bohr model electron is sphere .

The diameter of  Bohr is cut by N diameters of electrons in one C in time t.

The N  is number of electrons inside the electron cloud.

The dimeter of electron is

De=C/N

De=5.44x10^-11/1.44x10^15

De=3.73x10^-26m

To check this results we are going to use the same procedure but we are going to use entirely different force.

Fg=6.65x9.1x10^-31x 1.6x10^-27/26.98x10^-22

Fg=3.46x10^-47

Jg=Fg x t

Jg’=Fgxt’

Jg’=3.46x10^-47x 0.15x10^-15

Jg=0.51x10^-62

Ng=Jg/Jg’

Ng=3.46x10^-47/0.519x10^-62

Ng=6.78x10^15************

Opinions ?

2 minutes ago, jv1 said:

Opinions?

Did you get this from Ai? The format looks Ai ISH. The "old" quantum model was superceded, electrons do not "travel," in that way, North to South.

We have a few experts here @joigus who will critique better than I.

The Bohr model is demonstrably wrong, though it’s based on correct elements of physics, so some of its predictions are correct (e.g. the energy levels). But electrons don’t have actual trajectories. Nor do they have a measurable size (experiments give an upper bound which is smaller than your number)