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Quick question regarding hydrogen ignition pressure


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If I combine a compound which contain a ratio of 3/8 hydrogen/oxygen and heat it to 2600 F, according to PV = nRT 

how much will the pressure increase when it reaches ignition temperature (1058 F), and how big do I need the container to avoid it exploding and spewing lava everywhere?

Yes I am noob so please talk stupid to me. 

The compound has only hydrogen, carbon, oxygen and nitrogen.

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First what is the volume of your container

Roughly you can calculate you have 3 part H2 and 8 part O2 means together 11 part equal to mol.

Convert Fahrenheit to Kelvin

1058 F = 843,15 K

p = 11 mol*8.314 J/molK* 843,15K/ V m^3

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2 hours ago, Lahearle said:

If I combine a compound which contain a ratio of 3/8 hydrogen/oxygen and heat it to 2600 F, according to PV = nRT 

how much will the pressure increase when it reaches ignition temperature (1058 F), and how big do I need the container to avoid it exploding and spewing lava everywhere?

Yes I am noob so please talk stupid to me. 

The compound has only hydrogen, carbon, oxygen and nitrogen.

Won't the answer depend on what the products of decomposition are going to be, as well as on the enthalpy change, which may heat the mixture further ? Both of these will depend on what your undisclosed compound is.

Also, why do you speak of "lava"? Lava is molten rock and rocks do not ignite, as a rule.

 

Edited by exchemist
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