Ahh sorry im already stuck on a question. I just need help getting started.

 

Anyways this is the question

 

A tennis player serves a ball horizontally, giving it a speed of 24 m/s from a height of 2.5 m. The player is 12 m from the net. The top of the net is 0.90 m above the court surface. The ball clears the net and lands on the other side. Air resistance is negligible.

a)For how long is the ball airborne?

b)What is the horizontal displacement?

c)What is the velocity at impact?

d)By what distance does the ball clear the net.

 

I have no idea how to start this. I dont even know what i have. Can you please help me.

I always find it easier to draw out these problems.

 

You need to remember the starting height.... 24m/s velocity & graivty (otherwise it would never hit the ground, remember it was served horizontally)

 

Just to expand a little further on that... thinking about the tennis ball's path, you have it hit with a velocity of 24m/s and then there's gravity causing a downwards acceleration of 9.8 m/s^2

 

That might help, it depends just how stuck you are! Try drawing out the question, it's often easier to visualise that way.

that velocity is horizontal so it doesnt really do anything with the gravity. The confusing part for me are the two heights. Do i find the difference or add them

What kinematics equations have you learned that might apply here?