observer1 Posted January 13, 2023 Share Posted January 13, 2023 CaCO3 + 2CH3COOH ---> Ca(CH3COO)2 + H2O + CO2 If i add 2 moles of calcium carbonate and 2 moles of vinegar, how much of each of the result will i get in moles or grams? Link to comment Share on other sites More sharing options...
exchemist Posted January 14, 2023 Share Posted January 14, 2023 On 1/13/2023 at 1:29 PM, observer1 said: CaCO3 + 2CH3COOH ---> Ca(CH3COO)2 + H2O + CO2 If i add 2 moles of calcium carbonate and 2 moles of vinegar, how much of each of the result will i get in moles or grams? Show us how you are going about this, first. Link to comment Share on other sites More sharing options...
observer1 Posted January 14, 2023 Author Share Posted January 14, 2023 nvm i found it anyways Link to comment Share on other sites More sharing options...
apprentus Posted March 15, 2023 Share Posted March 15, 2023 The balanced equation shows that 1 mole of calcium carbonate reacts with 2 moles of acetic acid (vinegar) to produce 1 mole of calcium acetate, 1 mole of water, and 1 mole of carbon dioxide. Therefore, if you add 2 moles of calcium carbonate and 2 moles of vinegar, all of the vinegar will be used up since there is enough vinegar to react with both moles of calcium carbonate. The reaction will produce: 2 moles of calcium acetate (Ca(CH3COO)2) 2 moles of water (H2O) 2 moles of carbon dioxide (CO2) To calculate the amount of each product in grams, you need to know the molar mass of each compound. The molar masses are: Calcium acetate (Ca(CH3COO)2) = 158.17 g/mol Water (H2O) = 18.02 g/mol Carbon dioxide (CO2) = 44.01 g/mol So, the amount of each product in grams is: Calcium acetate: 2 moles x 158.17 g/mol = 316.34 g Water: 2 moles x 18.02 g/mol = 36.04 g Carbon dioxide: 2 moles x 44.01 g/mol = 88.02 g Therefore, if you add 2 moles of calcium carbonate and 2 moles of vinegar, you will get 316.34 g of calcium acetate, 36.04 g of water, and 88.02 g of carbon dioxide. Link to comment Share on other sites More sharing options...
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