Really difficult questions and I cant get my head around them. I've tried multiple time however can't seem to get it right. Any help or answers would be most appreciated.

Question 1

A sandstone reservoir is 50m thick and 100m wide, it has a porosity of 10% and a permeability of 5×10−13m2, a density of 2.3×103kgm3 and a specific heat of 1000Jkg⋅°C. The rock temperature is 90 °C. The fluid has a density of 965.3kgm3 and specific heat of 3.8204KJkg⋅°

If my well spacing is 1000m, what is the amount of Heat in Place available if the injection temperature is 50 °C?

Heat in place is given by HIP=Vres(Tprod−Tinj)×λ.

Bulk heat capacity of water-rock is given by λ=(1−ϕ)×ρrcr+ϕρfcf

Calculate the heat in place with injection temperature of 50 °C. Give your answer in scientific notation and one decimal like X.X * 10^(XX) Be sure to check the units.

Question 2

 

What is the flow rate needed to generate 1MW of thermal power from the sandstone of the previous question? Give your answer in scientific notation wih two decimals like X.XX * 10^(X). Power is given by: P=ρfcf(Tprod−Tinj)Q

 

15 minutes ago, Countygirl said:

A sandstone reservoir is 50m thick and 100m wide, ...................................

If my well spacing is 1000m,

Are you sure of these three figures ?

 A well every kilometre on a strip that narrow?

thats what the question says thats why its so confusing

OK so be it.

So you have the volume of the 'reservoir' available to each well.

You are given the density, porosity (phi if I am not mistaken) and specific heat of the rock and injected fluid.

So you can do a "heat gained by fluid  = heat lost by rock" calculation to establ;ish Tprod, which I assume is the eqyilibrium temperature produced.

Thus you can substitute into the first equation (HIP) given.

 

Where do you think the permeability comes into things ?

You need to show some working, we don't do the calculations for you, but might help you check them.