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Moon elevator


MaximT

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I want to discuss the possibility to build an elevator on the Moon surface...

There are some data:

cable.thumb.jpg.9acac71551525ca53c3dba6cb1a6a009.jpg

Basically, the speed on the surface will have to follow this rule: (where u = 4.905E12 m²/s)

Equation_1.jpg.75d1d817731d0b837365fd7c5c96ab41.jpg

 

The limitation, for the length of the cable is 4,500 km high...

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6 hours ago, swansont said:

your equation can’t work, since it has the wrong units.

In fact, you are right, My mistake, sorry:

 

In celestial mechanics, the standard gravitational parameter μ of a celestial body is the product of the gravitational constant G and the mass M of the body.

μ=GM

For several objects in the Solar System, the value of μ is known to greater accuracy than either G or M.[11] The SI units of the standard gravitational parameter are m3s−2. However, units of km3s−2 are frequently used in the scientific literature and in spacecraft navigation

 

15 hours ago, MaximT said:

Basically, the speed on the surface will have to follow this rule: (where u = 4.905E12 m³/s²)

Equation_1.jpg.75d1d817731d0b837365fd7c5c96ab41.jpg

This equation is derived from the circular orbit speed, as described in literacy:

Circular_Orbit.thumb.jpg.26b6c8ad4572864a95f33d6f089e2c3a.jpg

15 hours ago, MaximT said:

The limitation, for the length of the cable is 4,500 km high...

It's simply the breaking strength, in the spreadsheet, related to the mass of the cable, In it's most simple expression, but with centripetal force applied.

Edited by MaximT
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