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Irreversable Nuc [C anion]

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The strong CH3 Nuc would deprotinate the OH rather than react with the ketone? If so is there a lewis acid source to protinate the O?

Could I also get a hint on how the strong C [excess] would impact the compound?

Screen Shot 2018-01-28 at 2.28.24 PM.png

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What is a supporting information document? Is that in the journal? We are not allowed to use references for the exam. I think they just want us to use our tool bag of Orgo 2 knowhow. It is supposed to be doable without it. sigh. I asked my GSI (graduate student instructor) and she said the first step is deprotination of the OH group. So I'm guessing if there's excess the C anion will deprotinate the OH and attack the ketone. The formal charges of the O's make me uncomfortable.

Screen Shot 2018-01-29 at 12.28.15 PM.png

Edited by nancy9494

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Never mind about this one. The professor went over it and the second step H3O+ is missing.

The first one OH deprotinated by the CH3 then protonated by the the H3O+.

Excess same as first but the another CH3 attacks the ketone and that is later protonated by H3O+ [The added CH3 is on a wedge]

 

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