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Production of ice in vacuum...

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Hi.

To turn 1Kg of water at 20ºC into ice at -10ºC, is this calculation correct? :

 

Cooling the water 20ºC = 20 x 1KCal = 20 KCal

Freezing 1 Kg = 80 KCal

Cooling ice 10ºC = 10 x 500 Cal = 5 KCal

 

Total = 105 KCalories must be extracted.

 

How to calculate the same under 50 mm Hg vacuum ?

 

Miguel

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