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mechnism reactions

Sarahisme
in Chemistry

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hey another questions guys....

 

isnt there one too many Hydrogens on the left most carbon atom (to the right of the arrow)??

  • Author

hmmm then i don't see how this mechnism reaction works....

 

does that OH coming in take that hydrogen away?

  • Author

also just a second quick question....

 

shouldnt the N on the right side of the arrow have a postive charge (+) on it?

No its got a neutral charge 3-0-3=0

 

~Scott

  • Author

right ok, cool

 

so would you be able to quickly explain (if you have time) how the first one works (in the initial post of this thread)??

so would you be able to quickly explain (if you have time) how the first one works (in the initial post of this thread)??

Tell you the truth this stuff is abit beyond me but I think you are right either one of the hydrogens on the first carbon should be removed or it should be carrying a negative charge.

oh and whats with the "3-0-3=0"??

Formal charge

 

~Scott

The first one is wrong. They screwed up the mechanism. There should be one less hydrogen on the carbon. The hydroxyl subtracts the hydrogen to give water and a double bond forms stabalising the carbon. The oxygen is left with a negative charge.

 

Yeah the question is messed up. Just count the number of hydrogens there is an imbalance.

yes, in the overall reaction, there is an extra hydrogen atom in the product. in the product, the carbon on the left should be bonded to two hydrogen. the third joins the hydroxyl radical

also just a second quick question....

 

shouldnt the N on the right side of the arrow have a postive charge (+) on it?

 

if the hydrogen was to leave with the electrons yeah it would have a positive charge but this wouldn't happen.

 

Just to clear it up but what would likely happen is the hydrogen would remain, the nitrogen would then have a positive formal charge. This hydrogen would then be acidic and could easily be lost leaving behind a lone pair.

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