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Physics 1401

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If the pressure of water flowing through a 5.6×10^(2) −m -radius pipe at a speed of 1.2 m/s is 2.2 × 10^(5) N/m2.

 

Part A was What is the flow rate of the water?

I was able to get this because Q=vA

 

Part B was "What is the pressure in the water after it goes up a 4.4 −m -high hill and flows in a 4.1×10^(2)−m -radius pipe?"

 

I don't understand Part B can anyone help me?

When the pipe diameter changes what is affected ie does the volumetric flow rate (Q) or the velocity change?

 

You need the Bernoulli equation to complete the problem.

 

https://www.google.co.uk/search?hl=en-GB&source=hp&biw=&bih=&q=bernoulli+equation&gbv=2&oq=bernoulli&gs_l=heirloom-hp.1.0.0i131j0l9.9672.12515.0.14375.9.6.0.3.3.0.125.639.3j3.6.0....0...1ac.1.34.heirloom-hp..0.9.733.EiwTpT6g1fU

Edited by studiot

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