Gareth56

Many many thanks.

Given:

t₁=0.69s

t₂=2.37s

g=9.81m/s²

 

[math]h=\frac{(h+0.5g{t_1}^2)t_2}{t_1}[/math]

Multiply both sides by t₁ and distribute the t₂.

[math]ht_1=ht_2+0.5g{{t_1}^2}t_2[/math]

Get all your terms with the h variable to one side.

[math]ht_1-ht_2=0.5g{{t_1}^2}t_2[/math]

Factor out h.

[math](t_1-t_2)h=0.5g{{t_1}^2}t_2[/math]

Divide both sides by the coefficient of h.

[math]h=\frac{0.5g{{t_1}^2}t_2}{t_1-t_2}[/math]

Now, you just have to plug in your given values.

Does it matter that (0.5gt2^2) isn't included in the above solution because when plug in the numbers I should get 8.02m but for some reason I don't.

Does anyone know what the steps are to get "h" at just one side of the "=" sign? It's an equation from a physics book whih I just can't work out how the answer h is arrived at.

t1 = 0.69s & t2 = 2.37s g =9.81m/s

h =(h+0.5gt1^2)/t1)t2 - (0.5gt2^2)

The answer is h = 8.02m

Many thanks

G56