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Fuzzwood

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Posts posted by Fuzzwood

  1. Oh air most certainly has a mass. Why do you think a balloon falls toward the ground?

     

    Answer: the balloon has a certain overpressure (you felt this one if you ever blew up a balloon). Due to this pressure, the air molecules are compressed a little towards eachother, resulting in the density of the air inside the balloon to exceed the density of the air around it. The air inside the balloon is thus a bit heavier than the air around it and thus the balloon falls at your feet.

  2. No, I will say because of the kinetic energy that was gained from the exchange of potential energy. And I never stated such physics were simple. Oh, they are if you realize it is a simple matter of equalling Ek to Ep. 0.5 * m * v2 = m * g * h, but filling in the variables with the correct values can sometimes be a chore. ;)

     

    In a circular orbit, velocity is a constant. In an elliptical orbit, the velocity is variable with a maximum at the closest distance and a minimum at the furthest distance assuming 2-body physics. The latter part means that I don't account for overcomplicating stuff like the moon or that the sun is orbiting something else. You should take something home from this: never overcomplicate physics if you can get away with an educated guess. This needs a quote.

     

    https://www.youtube.com/watch?v=-E7h3vJXM08

  3. With a circular orbit you have equal radii for R1 and R2, and thus there is no exchange of kinetic for potential energy. The total energy of the system stays the same however. This is also the case in which R1>R2, e.g. an elliptical orbit. In this case there is a tradeoff between Ek and Ep. Ek starts to increase when a satellite moves from Apoapsis to Periapsis (points when the radius is the biggest (R1) or smallest (R2)), trading for Ep and increasing velocity, and vice versa when the satellite moves back to Ap from Pe.

     

    To answer the post where you respond to the mod comment:

     

    1) There are no thermodynamics involved as there is no significant heat exchange involved (as long as the meteor or whatever doesn't encounter the atmosphere that is). However you are correct in stating that such a system indeed has a certain total energy.

     

    2) It is EXACTLY WHY you still feel your body mass that there is a normal force!. If there weren't a normal force you would be weightless! Not massless, mind you, but you would be weightless!

     

    3) Your hammer indeed leaves a dent in the sand. It is not filled up because the moment your hammer leaves that dent that there is no normal force present to resist your hammer.

     

    4) There is no air pressure tag because it is simply assumed that there is no friction of air in those models (again, not to overcomplicate stuff). Weight is already accounted for in the gravitational force. Mass is NOT weight. Weight is actually defined as F = m*a. So yes, everyone saying that they weigh a certain amount of kg is raping physics.

  4. You won't need the chain. In an orbit, the kinetic energy with a vector along the velocity of the object will equal the gravitational or potential energy pointing to the mass at the center of the semimajor axis of the orbit. So the object is constantly falling towards the center of mass (and the center of mass towards the object) but the velocity and thus the kinetic energy is enough to keep the object in that particular orbit. Alos, changes in velocity will influence the orbit and if the velocity exceeds the escape velocity, the object will break orbit, or never enter an orbit to begin with as with your Hayley's comet. This does NOT mean that the vector of the comet is not influenced by the Earth's gravitational field.

     

     

    (and before you ask: no that isn't me, but I can derive the equations as needed. Also, kerbal space program © is awesome.)

  5. 1) You will still have the vibrational zero-point energy.

    2) There is always some form of EM radiation or even gravity wells in the known universe. So no.

     

    I expect and invite someone more educated in physics to beat me around the head now. :)

  6. I associate force with energy <-- and that is where you go wrong. Force has a unit of kg*m/s². Energy is measured in

    kg * m2/s2 or a force multiplied by a distance. Even with a distance of 0 and thus no applied energy, there can still be a force.

     

    Also, stop overcomplicating things if you do not understand the basics of something. It seems you fail at the progress of abstracting a physical phenomenon.

     

    To help you, you are indeed correct in saying that something doesn't fall through a table as long as molecular cohesion (forces like atom bonds, van der Waals forces, dipole interactions, etc.) inside that table is maintained. The moment that particular force is overcome by something with a very high mass, the table simply breaks. Until that point, however, the table will exert a force equal but opposite to the gravity force.

  7. It is theoretically impossible for the ground to push back. <-- and yet it does.

     

    In your elevator-example, the elevator will just keep falling with an acceleration of 9.81 m/s². Put a floor under it, strong enough to support the elevator, and the elevator will of course stop. Yet the force pulling at the elevator that can potentially give it an acceleration of 9.81 m/s² remains. So with no compensating force, the elevator will keep falling.

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