robotochan

I'm at Warwick uni' date=' you Coventry person you

 

What year you in?[/quote']

 

I'm off to warwick after my gap year, what you studying (some kind of engineering i presume)

 

I'm suprised you put your faith in teh british justice system, my brother got GBHed had to have a metal plate in his head he gave the name of the kid who did it to the police and nothing came of it, Can bolt cutters cut though a yale lock thing?

 

also does your phone have normal screws on it to get at the circuits, mine has crazy nuts with stars instead of a slit, where can i get tools to unscrew them?

Asimov and others have been saying that no work is being done because no distance is moved, but is that no the same for the stationary boat using 1000hp to maintain equilibrium. So clearly you have to take your distance with relation to the water not the actual position in space. Meaning as the anchor is providing a force and is going a distance (relative to the water as previously explained) it is doing work. as the speed of the river in both cases is the same, i would say it would be doing 1000hp of work, but i cannot work out where this energy is comign from, in the engine example it is comign from the fuel, here i dont get it, is it e.p.e or strain energy or somthign, but that doesn't make sence as thats liek a gain of energy with regards to the system which is impossible. It is a rather confusing senario, but i dont think you can say as it isn't moving no work is bing done, as this would be the same for the motorised boat but we have been told it is doing work.

i would absolutely love to hear how to do that without calc.

 

unless its a trick question' date=' which is an option im working on right now.[/quote']

 

its totally easy to do without calculus, your thinking of using differential equations to solve it but it doesn't need that.

 

you can work out the volume of the sphere and the volume of the bath, the only problem is the wording in this question. Im not sure wheather it means teh diamiter of the sphere decreses at 1.5mm/m or wheather it means the bath fills and 1.5mm/m if its the later then its really really easy, becasuse the bath is 0.8m high and it fills by 0.0015 m/m its then really simple maths. If it is the former its a little harder but only a little you need to work out the rate at which the sphere's volume changes, which i suppose you could use calculus for but you dont have to, and once you know this its just a matter of putting it into the worked out volume of the bath.

 

P.S i havent been part of this forum whats a neo nerd? and what are neo points, i want some now they sound cool. the more i get the more i become liek neo right and can fly and stuff yeh?

I think all of you have over simplified this. I took it as an equal probability of the following meetings (d=dominator s=sharer)

1/4 D+D, 1/4 D+S, 1/4 S+S, 1/4 S+D. I then took the number of offspring that would be produced D+D = 12D (dont think of it mathematically) D+S = 12D+8S S+S=12S and S+D = 8S+12D, (i have added into the equations the partners they might meet but only done it for the meetings of each group.) therefore when you add up the amount of each you have 28Sharers and 36Dominators, which using ratios then for a total of 2000 will give you the answer that for some reason i cant give, so wont. but i can pm it to you to check.

P.S what the hell is that furbles program for, i played with it for a while you cant even make them explode or fight or anything.

You cant be right about that helium thing i want proof. Surely the speed of the waves do not determing the pitch, the frequency does, by having the waves more faster just means it will reach your ear quicker, thing about it. If your voice box is vibrating at 30Hz (for example) it will make the changes in pressure of the helium be at 30Hz also. I have always been told that the reason helium makes your voice go funny is because it constricts the voice box (due to its lower desity) making it unable to produce the right sounds.

its very simple buddy you can never destroy any "information" so anything that goes into black hole comes out of it. it can not permanently be there in. it will take 100 billions years or more i dont know but it will come out of it. "YOU CAN NEVER DESTROY ANY INFORMATION" on the edge of event horizon you can not match the speed of light but after years of decay it is possible. if i believe other theory than it is possible that at the end there are only blackholes in the universe and than they pull each other and whole universe will again be point. and than again for a moment few nanoseconds all laws of physics vanish. And again a "BIGBANG" back to the square one.

I recently read in new scientist that "scientists" are comeign up with white hole therorys that say there are white holes where what entered a black hole exits, either in the same universe or in another universe.

He never specified how long he took to set up the experiment. Even if the acceleration of each train is only the acceleration of a starting snail they will reach near light speed eventually.

which is where the idea for solar sails came from.

In fact, only two of them do: the photon and the gluon (and the graviton if you want to count it). The other force carriers, the W+, W- and Z bosons have large masses, so they do not travel at c.

Hmm... thats spun me out, i thought photons were electromagnetic waves and hence the definition of the speed of light is their speed.

My addition to this thread is that It would be easier not to consider trains as this puts thoughts in our heads that do in no way mimic those of very fast moving things. If we thought of them as photons (or particles) moving relative to each other then it will be easier to understand. I will take it also as them moveing at 300km/s so with 1000 of these particles moveing as you describe the theory suggests that the finall one P1000 will be moving at 300,000km/s © Now, according to all of einsteins relativity work this should be impossible. But as the speed of light is irrelative (is that a word) and no matter how fast im moving it appears the same speed i.e if im movign 10m/s away from a ligth source pointed at me i will mesure its speed as cm/s not c-10 m/s this would give you the fact that if you were on P1000 it would mesure at c, and if you were at p1 p1000 would mesure at c also. I'm no physics proffesor so i couldn't tell you what this means. But i hope its helped to throw some ideas into your head. I think (but dont quote me on this) that as you move faster time slows down etc, so when observing p1000's speed compared to p999's speed from p1 you will not see a difference in speed of c but only a very small amount, however on p1000 as time is the same it will be as if you have travelled further in the same time. Am i right about that? I think that may be the solution to tyour conudrem if i am.