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Ducky Havok

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Posts posted by Ducky Havok

  1. umm... I tried using your time but I couldn't get it to work. 2:25, minus 20 would be 2:05. The mirror image of 2:05 would be 9:55, and that's 4 and a half hours apart. (please tell me if my reasoning somewhere along the line is wrong)

  2. A boy is leaving his house to go to class, and as he leaves he looks in the mirror and checks the time. Since the mirror is not digital and has no numbers, he mistakes it for correct (when in actualitly it was the mirror image.) He rides his bike for 20 minutes, and when he enters the room, he looks at the clock and notices it is 2 and a half hours later then when he thought he left. What time did he arrive at class?

     

    (it might help if you draw a picture :D )

  3. nevermind, I didn't see the negative in the previous one and that completely messed me up until I did it on paper. I get it now, -1/4 is equal to 1/4-1/2. I'm still curious about the other answer (1.4437374) though

  4. okay, I understand everything up until this point.

    [math]x^{x-\frac{1}{2}}=\left(\tfrac{1}{4}\right)^{\frac{1}{4}-\frac{1}{2}}[/math]

     

    Will you please explain how you got from the previous step to that one? Also, what about the other answer, 1.4437374? Is there a way to get that one?

  5. much like Cadmus said, its the order that matters. What you really should do is subtract that two at the end, and you get $25 for the room, not $29. I've heard this problem many times before btw... maybe you should have put it in the brain teasers section? I'm sure they'd like it

  6. It is just a technicality problem that 0.999...99 = 1' date=' because 1/9 = 0.999999...999. So there we go, deviding the contraversial "1" into 9 makes it equal to the contraversial 0.9999...999.[/quote']

     

    1/9=0.111111...111 ..... did you just mistype it or am I not understanding what you're saying?

  7. I simplified it to 1=(1/3)lnX+X, where X is less than or equal to 1, and greater than 0. That gives you a basic range and you could use logic. You know that if you use a decimal you'll have a negative with the natural log and when added to itself it can't add up to 1, so you could figure out that it has to be 1... I'm confused how to solve it algebraically though

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