rndomaccc Posted March 27, 2016 Share Posted March 27, 2016 A 3.50 kg ball with a velocity of 10.00 m/s collides with a stationary ball with a mass of 5.00 kg. After the collision, the first ball travels at a 42.6 degree angle from its original path, while the second ball travels at a -26.7 degree angle from the other ball's original path. 1) What is the momentum of each ball after the collision? 2) What is the velocity of each ball after the collision? Link to comment Share on other sites More sharing options...
swansont Posted March 27, 2016 Share Posted March 27, 2016 What work have you done so far? Link to comment Share on other sites More sharing options...
rndomaccc Posted March 27, 2016 Author Share Posted March 27, 2016 What work have you done so far? i have p = 3.50kg x 10.00m/s = 35.00 Ns i have no idea what to do from here Link to comment Share on other sites More sharing options...
swansont Posted March 27, 2016 Share Posted March 27, 2016 How do you apply conservation of momentum? Link to comment Share on other sites More sharing options...
rndomaccc Posted March 27, 2016 Author Share Posted March 27, 2016 How do you apply conservation of momentum? do you use m1v1i+m2v2i=m1v1f+m2v2f? Link to comment Share on other sites More sharing options...
swansont Posted March 28, 2016 Share Posted March 28, 2016 do you use m1v1i+m2v2i=m1v1f+m2v2f? Let's call the target object m2. What is v2i? Also, momentum is a vector, so we can (and will need to) write this equation for both the x and y directions (let's say v1i is in the x direction). What is v1iy? Link to comment Share on other sites More sharing options...
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