Razar Posted March 9, 2016 Share Posted March 9, 2016 Hi, I'm quite new to this forum so please correct me if I've done anything wrong or have gone against any rules! I was going through Organic Chemistry problems and this particular reaction had me stumped for a while. This is the answer to the whole reaction but I don't understand how the reagents affect the original molecule because I can't wrap my head around it. Any help would be greatly appreciated! Thanks Link to comment Share on other sites More sharing options...
BabcockHall Posted March 11, 2016 Share Posted March 11, 2016 (edited) What chemical properties does the anion in (1) possess? The starting material is an epoxide. What do you know about epoxides? Edited March 11, 2016 by BabcockHall Link to comment Share on other sites More sharing options...
Elite Engineer Posted March 15, 2016 Share Posted March 15, 2016 The first reagent is a strong anion that attacks one of the carbons in the epoxide molecule, opening up the epoxide molecule. The other 2 steps should be fairly easy to take from this. ~EE Link to comment Share on other sites More sharing options...
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