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Engineering question... please help


Billzey

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I`m currently studying an extended diploma in engineering and one of my assignment was referred and i have no clue how to correct it and my lecturer is no help at all. Could someone please give me a hand


slip gauge height 25mm using a 200mm sine bar

 

1) if DTI A is 2mm higher than B what is the angle of the component

 

2) if DTI B is 10 mm higher than A what is the angle of the component


here is the actual question sheet with some scruffy working out, sorry


i cant rotate it sorry

post-106404-0-05625900-1407921461_thumb.jpg

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I presume you (and your lecturer) know how to use a sine bar, the parts of the question you got wrong stem from the engineer's method of setting up.

 

Slips should be added or removed until the top surface of the workpiece is parallel to the surface table.

This can be done by trial and error or by the following 'quick' method.

 

1) Set up the bar and workpiece so the top surface is approximately parallel.

 

2) Take readings from the dial gauges noting the difference and which end is higher.

 

3) If B is lower than A add slips according to the proportion of the sine bar length to the work length.

 

4) IF A is lower than B remove slips according to the proportion of the sine bar length to the work length.

 

So where A is 2mm higher than B the slips need to be increased by {2 x (200/w)}mm, to set the workpiece parallel to the table. Where w is the worklength.

 

This gives a new slip height from which you can calculate the sine and thus the angle

Edited by studiot
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  • 2 weeks later...

the work piece length is 200 mm. this was a last resort as i have asked many others and still havent got an answer. i really need some help. the work piece is the sin bar

Edited by Billzey
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