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Some questions on strong interaction Rate Topic: -----

#1 5 January 2012 - 06:51 AM immijimmi 


Quark
1. Are quarks created with a specific color charge? For example in pair production a red up quark and a cyan antiup quark?

2. Why are there only 8 colour states for gluons? There are nine possible combinations of colour to 'anticolour'.

3. If there were only blue and red quarks but no green, would the strong force still have an effect and be able to bind quarks into hadrons?

4. Why is the strong nuclear/residual force transmitted by virtual pions, and since that's possible does it mean that all composite particles that have an integer spin (bosonic) can transmit a force in such a manner? (i.e. atoms such as helium 2)

If you know the answer to one and not the others just answer that one.

This post has been edited by immijimmi: 5 January 2012 - 07:27 AM

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#2 5 January 2012 - 10:49 AM User is online  swansont 


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Shaken, not Stirred
The gluon singlet state is not observed, leaving you with 8.
http://en.wikipedia...._singlet_states
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#3 10 January 2012 - 06:00 AM immijimmi 


Quark

View Postswansont, on 5 January 2012 - 10:49 AM, said:

The gluon singlet state is not observed, leaving you with 8.
http://en.wikipedia...._singlet_states


So, the gluon singlet state is a 'colourless' gluon? There are 3 of those, though... that means there are only 6 combinations:

r /b
r /g
b /r
b /g
g /r
g /b

The three that wouldn't be observed are:

r /r
b /b
g /g

So, why are there 8 observed?
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#4 10 January 2012 - 11:10 AM User is online  swansont 


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Shaken, not Stirred
The singlet state is identified in the link I provided — the symmetric superposition of the three color/anticolor pairings.
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#5 13 January 2012 - 12:20 AM Widdekind 


Atom
I understand, that the "singlet" gluon amounts, in effect, to an "all white (& anti-white)", i.e. "color-less" gluon, having no forceful effect what-so-ever:

g_s \approx g_{\bar{r}r} + g_{\bar{y}y} + g_{\bar{b}b} \approx g_{\bar{W}W} \approx g_{BW}

Could such a Strong-force "color-less", "black-and-white" gluon be compared, to a Weak-force "neutral current", i.e. Z^0 ??

View Postimmijimmi, on 5 January 2012 - 06:51 AM, said:

1. Are quarks created with a specific color charge? For example in pair production a red up quark and a cyan antiup quark?


I understand, that when gluon bonds "break", they "rip" at the "juncture" between their color & anticolor, creating a new quark & antiquark, having those color & anticolors:

g_{\bar{r}r} \rightarrow \bar{q}_{\bar{r}}'q_r'

I understand, that the new quark & antiquark become bound into new hadrons:

q_r : g_{\bar{r}r} : q_y q_b \rightarrow q_r \bar{q}_{\bar{r}}':q_r' q_y q_b \rightarrow q_r\bar{q}_{\bar{r}}'+q_r' q_y q_b

The resulting meson q_r\bar{q}_{\bar{r}}', is a pion, which "burps" from one baryon, to a neighboring baryon. The residual Strong nuclear force seems to stem, from the stressing & breaking, of intra-nucleon gluon bonds.

This post has been edited by Widdekind: 13 January 2012 - 12:24 AM

http://www.artofprob...p/LaTeX:Symbols
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#6 20 January 2012 - 04:18 PM immijimmi 


Quark

View Postswansont, on 10 January 2012 - 11:10 AM, said:

The singlet state is identified in the link I provided — the symmetric superposition of the three color/anticolor pairings.


Ok, but that still leaves six other observed states and not 8.

And, if r /r = colorless, which it does, why do I have to involve b /b and g /g? (as an example)

View PostWiddekind, on 13 January 2012 - 12:20 AM, said:

I understand, that the "singlet" gluon amounts, in effect, to an "all white (& anti-white)", i.e. "color-less" gluon, having no forceful effect what-so-ever:

g_s \approx g_{\bar{r}r} + g_{\bar{y}y} + g_{\bar{b}b} \approx g_{\bar{W}W} \approx g_{BW}

Could such a Strong-force "color-less", "black-and-white" gluon be compared, to a Weak-force "neutral current", i.e. Z^0 ??



I understand, that when gluon bonds "break", they "rip" at the "juncture" between their color & anticolor, creating a new quark & antiquark, having those color & anticolors:

g_{\bar{r}r} \rightarrow \bar{q}_{\bar{r}}'q_r'

I understand, that the new quark & antiquark become bound into new hadrons:

q_r : g_{\bar{r}r} : q_y q_b \rightarrow q_r \bar{q}_{\bar{r}}':q_r' q_y q_b \rightarrow q_r\bar{q}_{\bar{r}}'+q_r' q_y q_b

The resulting meson q_r\bar{q}_{\bar{r}}', is a pion, which "burps" from one baryon, to a neighboring baryon. The residual Strong nuclear force seems to stem, from the stressing & breaking, of intra-nucleon gluon bonds.


How is gluon fission relevant to whether quarks have color charge at creation? I mean, sure, you're showing how quarks with c-charge can be created from a gluon, but that already has color charge to pass on. I'm pretty sure that quarks have color charge from creation, but I wasn't sure.
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#7 23 January 2012 - 09:08 AM Widdekind 


Atom
I understand, that "color", having three "hues", is mathematically equivalent, to quarks having a "spin S=1 like" property. Perhaps you could conceive of "color" as an "orientation", i.e. xyz, i.e. quarks are "x-oriented", "y-oriented", "z-oriented" ?

I understand, that "color" is as intrinsic of a property, as spin, i.e. all quarks must have some "color" state, at all times.
http://www.artofprob...p/LaTeX:Symbols
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