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I really need help!!!


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#41 rktpro

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Posted 18 May 2011 - 12:48 AM

Where is my +1? :lol:
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#42 kavlas

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Posted 19 May 2011 - 10:50 AM

48/2y is kind of ambiguous, since it could mean (48/2)y or 48/(2y), depending on what the author means.


According to the above 48/2 could be 24 ,or (48/1).2 = 96 ??, depending on what the author means ??

Since 2 = 1.2 ??

That is why i asked you how much is 48/2

Further more \frac{48(x-a)^2}{(x-a)} could be 24(x-a) ,or:

\frac{48(x-a)^2}{2(x-a)} = [\frac{48(x-a)^2}{2}].(x-a) = 24(x-a)^3

Of course it is up to you to answer or not.

I just wanted to show what i ment by asking those questions
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#43 DJBruce

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Posted 19 May 2011 - 08:36 PM

According to the above 48/2 could be 24 ,or (48/1).2 = 96 ??, depending on what the author means ??

Since 2 = 1.2 ??


No, what you have are two different expressions. Since 2=(1*2) you could write 48/(1*2), which would be 24.

Further more \frac{48(x-a)^2}{(x-a)} could be 24(x-a)


Ahh, not it cannot.

\frac{48(x-a)^2}{2(x-a)} = [\frac{48(x-a)^2}{2}].(x-a) = 24(x-a)^3



No it could not unless you completely change the standard convention of what the notation of [math]/frac{a}{b}[\math] means.
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#44 kavlas

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Posted 20 May 2011 - 11:17 PM

According to the above 48/2 could be 24 ,or (48/1).2 = 96 ??, depending on what the author means ??

Since 2 = 1.2 ??

That is why i asked you how much is 48/2

Further more \frac{48(x-a)^2}{2(x-a)} could be 24(x-a) ,or:

\frac{48(x-a)^2}{2(x-a)} = [\frac{48(x-a)^2}{2}].(x-a) = 24(x-a)^3

Of course it is up to you to answer or not.

I just wanted to show what i ment by asking those questions


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#45 deesuwalka

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Posted 12 October 2016 - 09:14 AM

You can simplify it easily,

 

 \frac{48}{2y}

 

Write this as,

 

 \frac{48}{2}\times\frac{1}{y}

 

Now, simply divide 48 by 2 and then multiply,

 

 24\times\frac{1}{y}=\frac{24}{y}

 

 I hope it' ll help.


Edited by deesuwalka, 12 October 2016 - 09:41 AM.

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