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About deesuwalka
- Birthday 10/17/1994
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mathametics
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Use percent calculator- http://www.math.com/students/calculators/source/3percent.htm
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[latex] \int\limits^2_0 \dfrac{x^2}{x^2-2x+2} dx [/latex] [latex] =\int\limits^2_0 \dfrac{x^2-2x+2+2x-2}{x^2-2x+2} dx [/latex] [latex] =\int\limits^2_0 1+ \dfrac{2x-2}{x^2-2x+2} dx [/latex] [latex] =\int\limits^2_0 dx+\int\limits^2_0 \dfrac{2x-2}{x^2-2x+2} dx [/latex] Let [latex] t=x^2-2x+2 [/latex] [latex] dt=(2x-2)dx [/latex] [latex] =\bigg[x\bigg]^2_0+\int\limits^2_0\dfrac{dt}{t} [/latex] [latex] =2+\bigg[\ln\,t\bigg]^2_0\;\;\implies\bigg[\ln(x^2-2x+2)\bigg]^2_0 [/latex] [latex] =2+\bigg[\ln\,2-\ln\,2\bigg] [/latex] [latex] =2+0=2 [/latex]
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Here is the solution- [latex] -8=\dfrac{3}{19}n [/latex] Now, multiply both sides by [latex] 19 [/latex] [latex] -8\times 19=\not19 \times\dfrac{3}{\not19}n [/latex] [latex] -152=3n [/latex] Now, divide both sides by [latex] 3 [/latex] [latex] \dfrac{-152}{3}=\dfrac{3n}{3} [/latex] [latex] \dfrac{-152}{3}=n [/latex]
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You have to switch the [latex]x[/latex] and [latex]y[/latex], and then solve for [latex]y[/latex]. [latex]y=x^7+x^5 [/latex] [latex]x=y^7+y^5 [/latex] [latex]x=y^5(y^2+1) [/latex] I think it can't be solved farther.
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Advise a selection of books for studying of mathematics with 0.
deesuwalka replied to SeTVP's topic in Mathematics
Right, there are millions of books available. I think you should prefer online study, there are many sites which help you https://www.khanacademy.org/ http://www.mathsisfun.com/) http://www.actucation.com/ -
[latex] \frac{x+y}{x-y}\times\frac{x-y}{x+y} [/latex] [latex] =\frac{\not x+\not y}{\not x-\not y}\times\frac{\not x-\not y}{\not x+\not y} [/latex] [latex]= 1 \times 1[/latex] [latex]= 1 [/latex]
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We can read the equations three types, [latex] \frac{x- x_{1} }{ x_{2}- x_{1} } =\frac{y- y_{1} }{ y_{2}- y_{1} } [/latex] [latex] \frac{x- x_{1} }{ x_{2}- x_{1} } =\frac{z- z_{1} }{ z_{2}- z_{1} } [/latex] [latex] \frac{y- y_{1} }{ y_{2}- y_{1} }=\frac{z- z_{1} }{ z_{2}- z_{1} } [/latex] So, I think it would be 3 equations.
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Use order of operation, i.e.,PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction) [latex] 36\div 6(2+2+2)= ? [/latex] First, Parenthesis- [latex] =36\div6(6) [/latex] Now, between multiplication and division, we apply operation which comes first, here division comes first so we apply division- [latex]= 6(6) [/latex] Now, applying multiplication- [latex]= 6(6)\;\;\implies 6\times6=36 [/latex] I hope it' ll help.
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We substitute [latex] \sqrt{9-x^2} [/latex] by [latex] x= 3sin\theta [/latex] because a trigonometric substitution</a> helps us to get a perfect square under the radical sign. This simplifies the integrand function.http://www.actucation.com/calculus-2/indefinite-integration/basic-methods-of-integration/integration-by-substitution-of-trigonometric-functions Now, we can simplified it easily, [latex] \int\sqrt{9-x^2}\;\;\implies\int\sqrt{3^2-x^2} [/latex] [latex] \int\sqrt{3^2-x^2}\;\implies\sqrt{3^2-(3sin\theta)^2} [/latex] [latex] =\sqrt{9-9sin^2\theta} [/latex] [latex] \sqrt{9-9sin^2\theta}\;\;\implies\sqrt{9(1-sin^2\theta)}\;\;\implies\sqrt{9cos^2\theta}\;=\;\int 3cos\theta [/latex] I hope it' ll help.
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You can simplify it easily, [latex] \frac{48}{2y} [/latex] Write this as, [latex] \frac{48}{2}\times\frac{1}{y} [/latex] Now, simply divide 48 by 2 and then multiply, [latex] 24\times\frac{1}{y}=\frac{24}{y} [/latex] I hope it' ll help.
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The number 11111..111111..11 (91)times is an?
deesuwalka replied to Rajnish Kaushik's topic in Analysis and Calculus
1. It's not an even number because it ends with 1, it's an odd number 3. It's not a prime number because it's divisible by 1,111,111 other than 1