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question about mass-energy equivalence
#2 6 September 2010 - 07:42 AM
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#3 6 September 2010 - 09:39 PM
ajb, on 6 September 2010 - 07:42 AM, said:
Nope does not work.
Look at section 6.
http://www.fourmilab....html#SECTION21
You can go one way or the other.
Einstein uses these SR Maxwell equations to derive the mass energy equivalence. However, each requires a constant measured value of c. But, in a rotating frame, measured c is directionally and v dependent and not a constant.
If that is not enought, you cannot sync clocks in a rotating frame. Note Einstein takes partial derivatives with respect to tau.
You cannot take the derivative unless you have a free and consistent variable. But, since you cannot sync clocks in a rotating frame, then you do not have a free variable tau and hence you cannot take the partial derivative.
This post has been edited by vuquta: 6 September 2010 - 09:40 PM
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#4 7 September 2010 - 10:19 AM
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#5 8 September 2010 - 02:13 AM
swansont, on 7 September 2010 - 10:19 AM, said:
Einstein takes the partial derivative with repect to tau for the Maxwell transformations.
How are you going to do this in a rotating frame?
Why are we getting off task? This is a simple question.
This post has been edited by vuquta: 8 September 2010 - 02:17 AM
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#6 8 September 2010 - 10:31 AM
vuquta, on 8 September 2010 - 02:13 AM, said:
Yes, and he does this in an inertial frame.
vuquta, on 8 September 2010 - 02:13 AM, said:
Why are we getting off task? This is a simple question.
Even though you can't synchronize clocks, the rate (i.e. frequency) is offset by a constant amount. You would probably have to approach this by accounting for this offset, much like one would add in a pseudoforce to make a non-inertial system "look" inertial (Coriolis or centrifugal) in analyzing forces.
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#7 8 September 2010 - 11:48 PM
swansont, on 8 September 2010 - 10:31 AM, said:
Even though you can't synchronize clocks, the rate (i.e. frequency) is offset by a constant amount. You would probably have to approach this by accounting for this offset, much like one would add in a pseudoforce to make a non-inertial system "look" inertial (Coriolis or centrifugal) in analyzing forces.
No, this is wrong. The offset is not constant since it can involve a sphere.
The only way you can sync the clocks is using a resursive function and convert it to a Cauchy sequence to prove it converges to the correct rotational direction. Then and only then can you sync clocks. And the synchronization is a function of direction. Perpendicular, they are synched and parallel to the rotation they are max unsynched. This is fact is a cosine function and certainly not a constant.
This implies the partial derivatives are wrong for a rotating frame and should be using some form of the chain rule but only after the direction has been established.
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#8 9 September 2010 - 10:46 AM
vuquta, on 8 September 2010 - 11:48 PM, said:
It works for GPS.
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#9 10 September 2010 - 11:53 PM
swansont, on 9 September 2010 - 10:46 AM, said:
Exactly, I told you how they do it.
You have to know the rotation of the earth.
If you check the GPS constants and such, you will find this "value" of the speed and rotation of the earth.
It is built into all calculations.
But, when you boot this system, you need a method to determine the rotational speed and exact direction/axis of rotation.
That is what I was giving you.
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#10 11 September 2010 - 01:18 AM
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#12 13 September 2010 - 12:26 AM
vuquta, on 12 September 2010 - 09:36 PM, said:
I guess I was confused by your assertion that the frequency offset cannot be a constant. You obviously meant something else by that.
vuquta, on 12 September 2010 - 09:36 PM, said:
And one uses the standard value of c in those calculations. So, do you have a point here?
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#13 13 September 2010 - 11:41 PM
swansont, on 13 September 2010 - 12:26 AM, said:
And one uses the standard value of c in those calculations. So, do you have a point here?
Absolutely you must use c for those calculations. That way, depending on the direction you can use the below to calculate the t. You then compare this to the t you would have if no rotation occured. The difference between the two is the sagnac correction.

So, all my logic was doing was establishing the absolute rotation of the earth since you cannot use ESP to figure it out.
This post has been edited by vuquta: 13 September 2010 - 11:42 PM
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#14 13 November 2010 - 02:55 PM
vuquta, on 5 September 2010 - 10:46 PM, said:
where
E=energy
M=mass
c= the speed of light
What value of c is used in a rotating frame?
http://www.fourmilab...tein/E_mc2/www/
Excellent question!
Einstein's theory of relativity was based on spherical radiation. I question that assumption, but for spherical radiation, there is a radius and and angle that affects what you see at various points along the frame. In addition, this variation is not constant but varies with distance.
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