gyytyg Posted January 30, 2017 Share Posted January 30, 2017 (edited) 14.3g of an oxide of copper contained 12.7g of copper calculate the empirical formula of this oxide relative formula masses Cu= 63.5 O=16 please help this is what I done 12.7/63.5= 0.2 I am not sure about the rest Edited January 30, 2017 by gyytyg Link to comment Share on other sites More sharing options...
Sensei Posted January 30, 2017 Share Posted January 30, 2017 14.3g of an oxide of copper contained 12.7g of copper calculate the empirical formula of this oxide relative formula masses Cu= 63.5 O=16 please help this is what I done How many Copper oxides do you know? How to calculate molar mass of compound? How to calculate percentage of one element in compound? 12.7/63.5= 0.2 I am not sure about the rest It's not correct. Link to comment Share on other sites More sharing options...
dill Posted February 8, 2017 Share Posted February 8, 2017 If the 14.3 gram compound contains only copper and oxygen atoms and 12.7 grams of it is copper, how much of it is oxygen (in grams)? With that, how many times more copper than oxygen is there in the compound? Now, the atomic mass of copper is how many times greater than the atomic mass of oxygen?... Knowing these two ratios, you should be able to determine the ratio of copper to oxygen atoms in the compound to get the empirical formula! Link to comment Share on other sites More sharing options...
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