Cyanide Posted March 15, 2005 Share Posted March 15, 2005 I worked out the problem...I'm just not sure if it's correct. A baseball is popped straight up into the air and has a hang-time of 6.25 s. Determine the height to which the ball rises before it reaches its peak. It seems simple enough... First I used vf = vi + a*t I figured it out to be vi = 30.6 m/s Then I used vf^2 = vi^2 + 2ad My final answer was d = 47.9 m P.S. I'd be very grateful if someone would tell me if I'm in the right direction atleast Link to comment Share on other sites More sharing options...
jordan Posted March 15, 2005 Share Posted March 15, 2005 All looks good to me. Link to comment Share on other sites More sharing options...
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