md2 Posted June 3, 2014 Share Posted June 3, 2014 if we have function like this y = ( x - 2 ) ^ 2 + 1, what we will get if we do : y = - ( ( x - 2) ^ 2 + 1 ) , and more to find the top of function ( highest value ) doesnt matter the ( x - 2) ^ 2 ..... for x-2 beacause theres allways is 0 to find the top of function Link to comment Share on other sites More sharing options...
Greg H. Posted June 3, 2014 Share Posted June 3, 2014 First just to clarify, do you mean these functions? [math]y = (x - 2)^2 + 1[/math] and [math]y = -((x - 2)^2 + 1)[/math] Second, I don't know what you're trying to determine. Can you elaborate? Link to comment Share on other sites More sharing options...
CaptainPanic Posted June 4, 2014 Share Posted June 4, 2014 ! Moderator Note md2,You must write posts that we can understand. What do you want to ask or discuss? If you do not write posts that other people can understand, you cannot post on our forum. I hope you understand this warning.So far, nobody understood any of your posts. Link to comment Share on other sites More sharing options...
md2 Posted June 4, 2014 Author Share Posted June 4, 2014 (edited) and this part x ^ 2 also doeasnt matter, bacause the x ^ 2 after set the x = 0 will be 0, so in this function only matter + 1, to find the top of function. and b value must be > 0 , or < 0, its clear i am trying to find the maximum and minimum of this function. and what else use this equal y = b / x has sense ? and in equal y = (x-3)^2 + 2, line provide by minimum of this function is y = 3 / 2 x . with equal (x-6)^2 + 1 the line provide by minimum of this function is y = 1/6 x Edited June 4, 2014 by md2 Link to comment Share on other sites More sharing options...
md2 Posted June 4, 2014 Author Share Posted June 4, 2014 (edited) and what more (b) cant be more ( for x^2 + b ) next values for example : y = x^2 + b, x = 1, x = 2, maximum is only 1 point and the b < x^2 + b Edited June 4, 2014 by md2 Link to comment Share on other sites More sharing options...
md2 Posted June 5, 2014 Author Share Posted June 5, 2014 (edited) y = (x - 2)^2 / b , for maximum of function y = (x - 2 )^2 + b , for maximum y = 0 , when x = 2 y y = ( x - 3 ) ^ 2 + b b < ( x - 3 ) ^ 2 Edited June 5, 2014 by md2 Link to comment Share on other sites More sharing options...
md2 Posted June 6, 2014 Author Share Posted June 6, 2014 (edited) b = ( x - 3 ) ^ 2 + b Edited June 6, 2014 by md2 Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now