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md2

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Everything posted by md2

  1. md2

    howard web

    i supose howard web dont fair ride the match
  2. diameter of sphere is 2 pi r, but from what point of view
  3. md2

    side to side

    next values : I : 2 + 2 ^ 2 II : 2 + 2 ^ 3 III : 2 ^ 1 + 2 ^ 2 + 2 ^ 3
  4. md2

    square

    a ^ 2 = d ^ 2 / 2
  5. md2

    high and equal

    high of triangle same-side around the circle is 3 r, to 2r ( 2 ray of circle ) 2 ray of circle to diagonal of square inside the circle is 2 to 2 / sqrt(2)
  6. md2

    dimensions

    ( 2 ^ 2 ) ^ 2 is not like 2 ^ 3 in dimenosion for examp
  7. md2

    collision center

    collision of hadrons, but what is it hadron ?
  8. md2

    2r of oval

    suggestion : 2r is diagonal of square inside the oval
  9. md2

    sphere

    based on ricle r = 1, course is side of square around of circle, and diagonal from eaual of area of circle, this three values are course of next circle rays and 2 r / sqrt ( 2 ) = sqrt ( 2 ) for r = 1
  10. md2

    sphere

    is it a dependence between d ( diagonal of square from equal of area of circle ) to r ( ray of this circle ) d / r pi * r ^ 2, pi * sqrt(2) ^ 2, d = sqrt(2) * d ( for third value ) ....
  11. md2

    function

    b = ( x - 3 ) ^ 2 + b
  12. md2

    function

    y = (x - 2)^2 / b , for maximum of function y = (x - 2 )^2 + b , for maximum y = 0 , when x = 2 y y = ( x - 3 ) ^ 2 + b b < ( x - 3 ) ^ 2
  13. md2

    function

    and what more (b) cant be more ( for x^2 + b ) next values for example : y = x^2 + b, x = 1, x = 2, maximum is only 1 point and the b < x^2 + b
  14. md2

    function

    and this part x ^ 2 also doeasnt matter, bacause the x ^ 2 after set the x = 0 will be 0, so in this function only matter + 1, to find the top of function. and b value must be > 0 , or < 0, its clear i am trying to find the maximum and minimum of this function. and what else use this equal y = b / x has sense ? and in equal y = (x-3)^2 + 2, line provide by minimum of this function is y = 3 / 2 x . with equal (x-6)^2 + 1 the line provide by minimum of this function is y = 1/6 x
  15. md2

    function

    if we have function like this y = ( x - 2 ) ^ 2 + 1, what we will get if we do : y = - ( ( x - 2) ^ 2 + 1 ) , and more to find the top of function ( highest value ) doesnt matter the ( x - 2) ^ 2 ..... for x-2 beacause theres allways is 0 to find the top of function
  16. about the highest and lowest of function, if we get the lowest value of function like sinus and cosinus ( exmaple ) , od minus them we get the medium of function, but the doing it on back, we maybe get the lowest and hightest of this function and if we get y = 2x + 1, and change it to 2x - 1, we can do 2x + 1 / 2x - 1, and dont know if it will make something
  17. picture : http://s6907.chomikuj.pl/ChomikImage.aspx?e=BNis-wCuwcNDkpjatdNzsgfVQtxAral5imWMh2pcl5i3we1zEJnLAb22thcIwURy0BZgsnZ7wrNEOE4LLgkqslbSC1Gc0yINw0Y-KxmPKgc&pv=2
  18. the area of square around the circle is countable
  19. area of square inside the circle is undimensial, because if we get the side of this square according to ray of circle we will get the undimensial area am i correct ?
  20. md2

    logarithm

    so i remember, logarith is dependence between a to c in a^b = c so if we have 5 ^ 3 = 125 between 125 and 5 is dependence 125 / 5 = 25, so squart from 2 = 25
  21. earth isnt so stupid as it looks like
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