Jump to content



Recommended Posts

solve what?


i assume u mean finding the root of that function


it looks like u will need to find the roots of a quartic of a form ax^4 + bx^3 + c = 0

there should be a general formula for that, i dont know it. lemme just try to look for it on the net

Link to comment
Share on other sites

well do it this way.





then -1 iby inspection is a root, therefore (x+1) is a factor of f(x). then you can reduce the polynomial into a quintic


information on solving quartic


there is also a link at the bottom to solutions to quintic


I banged the equation into Maple, and the solutions are horrible. the only nice solutions is -1, the others are massive strings of numbers.

Link to comment
Share on other sites

I think he meant intervals instead of integrals, but I could be wrong.


All the other integral roots.


You have an equation which ends in a prime. To factorise it into an (x+a)(x+b)(x+....) form, a*b*c*whatever must equal the prime. To get integral values, one of those numbers must be the prime, and the rest must be one, by the definition of a prime number.


As it's fairly clear that 2 is not a factor, the solutions therefore can't be nice integrals.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.