what's the value of ~(char)(!!9) ? Again, good luck.

are u ATIPROCHARGEDGM on LS1.com??

 

im ELS1 from the forums

 

found this here: http://www.ls1.com/forums/showthread.php?threadid=127788

 

 

Yep.

first off the !!9 = 1 . ! (not operator) returns 0 if the value is non-zero, so !9 = 0 !!9 = !0 = 1, or the same as saying if not 9 = 0 in the possible answers of 0 and 1, then not not 9 must equal 1. !!!9 would then = 0 and !!!!9 = 1, and so on.

the ~ (tilde) operator is a bit-wise one's complement, which is very easy just invert all the bits

!0001100 = 1110011

so lets assume you have a one byte value, which when you said (char), makes it. it equals one (0000 0001) now if you perform a one's complement on that number you should get

1111 1110 which would be either 254 or -2 , negative numbers in binary or such a pain

you have to know when your dealing with them in assembly, c++ and other high languages take care of this for you, thats why you have to specify signed/unsigned if you need the extra space cause in signed variables the last bit is needed as the sign bit, 1 = negative, 0 = positive.

i was wondering why a link to this place was on the corral.net forums...but im glad i saw it.

Adrian is very active on that forum and offered to post on it on behalf of this site. We very much appreciate it

What about this thread on corral ? Give me the link.