Jump to content

catalyst


NwJosh

Recommended Posts

We've done an experiment on the rate of reactions using catalysts, we now have to do a right up of it and I'm stuck on explaining how the catalysts worked in the experiment i know that the help break chemical bonds in reactant molecules and provide a 'different pathway' for the reaction, but how do they do it.

 

The experiment was using 10cm3 potassium iodide solution, 10cm3 sodium thiosulfate solution, 5cm3 starch solution add the catalysts and then add 20cm3 of potassium peroxodisulfate solution

I've been told by my teacher that it is something to do with the shape of the molecule and the catalysts, but i cant remember exactly what she said, or that i understood it.

 

Edited by NwJosh
Link to comment
Share on other sites

First of all, you need to work out what reaction has occured; right out the chemical equation.

 

Once you have that, it might help to come up with the mechanism for this reaction (or at least what is turning tinto what).

 

Your right in that a catalysts provides the reaction with an alternative route to the product (and product to reagents; remember catalysts don't alter the position of equilibrium, just the rate at which you get there) which is lower in energy somehow.

 

Once you have an idea how the reaction occurs without the catalyst, look at the structure of the catalyst and then think how it might help the reaction. If your teacher told you it had to do with shape, then I would believe him/her.

Link to comment
Share on other sites

If you say this

gd (¬Î`(d héJ8° eˆ„ üƒÜ

3à4;€.ÖŽ÷îbad°

ÆÞ- Z*õòO&Íúû3©ã–·ß‡ºJTÊ+Öð͆­¢ÞŒ£¾]òì˜o ÛŒ*J J†9Ýöö¬—_0¾­Áå\Ko?£—(Ùy9Þ‹]šUŸãÆ1ü?,#•äUÈ ÐÇfçx>wd­e¤P

Link to comment
Share on other sites

If you say this

gd (¬Î`(d héJ8° eˆ„ üƒÜ

3à4;€.ÖŽ÷îbad°

ÆÞ- Z*õòO&Íúû3©ã–·ß‡ºJTÊ+Öð͆­¢ÞŒ£¾]òì˜o ÛŒ*J J†9Ýöö¬—_0¾­Áå\Ko?£—(Ùy9Þ‹]šUŸãÆ1ü?,#•äUÈ ÐÇfçx>wd­e¤P

 

Your equation isn't rendering on my browser. Try again with [ce] or [math] tags.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.