alpha2cen Posted January 6, 2011 Share Posted January 6, 2011 (edited) Let's think about this problem. This operation @ is consisted of two of multiplying or dividing plus one constant a(a=/ 0). a @ a= a 2 @ 3a = 2/3 2a@ 2 = a^2 1 @ 1 = ? hint @ : ( ) # ( ) # ( ) where ( ) means constant or variables where # means multiplication or division. The first operator searching problem. Edited January 7, 2011 by alpha2cen Link to comment Share on other sites More sharing options...
the tree Posted January 8, 2011 Share Posted January 8, 2011 I'm going to guess that x@y = x*a/y, so 1@1=a, but I wouldn't be able to say if that's a unique solution or not. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now