Gamewizard Posted December 20, 2010 Share Posted December 20, 2010 Hi Anyone good with statistics ? I just want to confirm something, not asking for answers. The standard error of the mean SEM, is it the square root of standard deviation or is it standard deviation divided by the square root of n, the sample number. Please can someone clarify, i have a test and I dont want to do the wrong thing. Link to comment Share on other sites More sharing options...
DJBruce Posted December 20, 2010 Share Posted December 20, 2010 (edited) Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is [math] SE = \frac{S}{\sqrt{n}}[/math] Edited December 20, 2010 by DJBruce Link to comment Share on other sites More sharing options...
Ludwik Posted December 21, 2010 Share Posted December 21, 2010 Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is [math] SE = \frac{S}{\sqrt{n}}[/math] Actually, n should be replaced by (n-1). But that does not matter when n>>1 Ludwik Kowalski (see Wikipedia) Link to comment Share on other sites More sharing options...
Gamewizard Posted December 21, 2010 Author Share Posted December 21, 2010 Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is [math] SE = \frac{S}{\sqrt{n}}[/math] so it is the square root of standard deviation ? or the second one Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now