Hi

 

Anyone good with statistics ? I just want to confirm something, not asking for answers.

 

The standard error of the mean SEM, is it the square root of standard deviation or is it standard deviation divided by the square root of n, the sample number.

 

Please can someone clarify, i have a test and I dont want to do the wrong thing.

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

Edited December 20, 201015 yr by DJBruce

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

 

Actually, n should be replaced by (n-1). But that does not matter when n>>1

 

Ludwik Kowalski (see Wikipedia)

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

 

so it is the square root of standard deviation ? or the second one