Caleb Posted April 30, 2010 Share Posted April 30, 2010 Here is a strange equation I found: a=b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) a + b = b (a = b) a + a = a 2a = a 2 = 1 This still works, even if you substitute "a" and "b". 2 = 2 2^2 = 2(2) 2^2 - 2^2 = 2(2) - 2^2 (2 + 2)(2 - 2) = 2(2 - 2) 2 + 2 = 2 4 = 2 Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted April 30, 2010 Share Posted April 30, 2010 You can't divide by a-b. a=b, so a-b=0. Division by 0. 1 Link to comment Share on other sites More sharing options...
sammy28 Posted May 2, 2010 Share Posted May 2, 2010 a=b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) a + b = b (a = b) a + a = a 2a = a 2 = 1 2 = 2 2^2 = 2(2) 2^2 - 2^2 = 2(2) - 2^2 (2 + 2)(2 - 2) = 2(2 - 2) 2 + 2 = 2 4 = 2 Link to comment Share on other sites More sharing options...
insane_alien Posted May 2, 2010 Share Posted May 2, 2010 a+a=a is only a correct equation if you throw out the rules of maths. starting from something that is false can lead you to any answer you want. of course a could always be zero then its fine. but 2(0) is still zero. Link to comment Share on other sites More sharing options...
Sisyphus Posted May 2, 2010 Share Posted May 2, 2010 Pretty much all of these types of fake proofs just involve dividing by zero at some point and hoping you won't notice. Link to comment Share on other sites More sharing options...
Caleb Posted May 3, 2010 Author Share Posted May 3, 2010 (2 + 2)(2 - 2) = 2(2 - 2) In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you? Link to comment Share on other sites More sharing options...
Charlatan Posted May 3, 2010 Share Posted May 3, 2010 Here is a strange equation I found:a=b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) a + b = b (a = b) a + a = a 2a = a 2 = 1 This still works, even if you substitute "a" and "b". 2 = 2 2^2 = 2(2) 2^2 - 2^2 = 2(2) - 2^2 (2 + 2)(2 - 2) = 2(2 - 2) 2 + 2 = 2 4 = 2 Two can equal one, but not practically. Theories about two eqaulling one is incorrect. If a = b, and they are different, then there is aporblem with the question. It is false! If one thing equals another, they are just dirrent names. Peter is Paul, for example. That could come from an alias of second name, so, you could say anything and put a question mark behind it! Yes two can equal one, but not pyhsically. Two is a name of something, but, in computer language they cannot be the same. Computer's work off of binary, or, mathematical processors [although Isuggested science based ones], and they will be on or off. One set cannot equal a different set. Link to comment Share on other sites More sharing options...
ajb Posted May 3, 2010 Share Posted May 3, 2010 In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you? 2-2 = 0 Division by zero is indeterminate, don't do it! Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted May 3, 2010 Share Posted May 3, 2010 In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you? "Canceling out" is division. (a + b)(a - b) = b(a - b) Since (a - b) is 0, b and (a + b) could be anything and the equation would still be true -- each side would still be 0. If a = 2, they'd be 2 and 4, respectively, but the equation would be true. Try to divide out (a - b) and it'd no longer be true. Link to comment Share on other sites More sharing options...
Caleb Posted May 3, 2010 Author Share Posted May 3, 2010 "Canceling out" is division. (a + b)(a - b) = b(a - b) Since (a - b) is 0, b and (a + b) could be anything and the equation would still be true -- each side would still be 0. If a = 2, they'd be 2 and 4, respectively, but the equation would be true. Try to divide out (a - b) and it'd no longer be true. Oh, okay. That makes sense. Thanks Link to comment Share on other sites More sharing options...
PaulS1950 Posted May 4, 2010 Share Posted May 4, 2010 and if you don't cancell anything (which you do): Here is a strange equation I found: a=b a^2 = ab a^2 - b^2 = ab - b^2 (a + b)(a - b) = b(a - b) [(2a)(0) = (b)(0)] = 0 = 0 a + b = b.......................reassigned values a + b = 0 (a = b)..........................reassigned values a = b = 0 a + a = a.......................0 + 0 = 0 2a = a..........................2 x 0 = 0 2 = 1...........................0 = 0 The simple fact is that zero will almost always cause conflicts which is why it is not a number. exceptions?: 0/0 = 1 any number divided by itself is 1 (I know) 0n = 0 (I know) n/0 (if n<>0) = infinity (Yes I know) "I know" = zero is not a number - it is a place holder. Link to comment Share on other sites More sharing options...
the tree Posted May 4, 2010 Share Posted May 4, 2010 The simple fact is that zero will almost always cause conflicts which is why it is not a number. *face* *palm* Link to comment Share on other sites More sharing options...
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