alejandrito20 Posted April 23, 2010 Share Posted April 23, 2010 In the einstein equation [math]R_{uv}-0,5 R g_{uv}+ \Lambda g_{uv} = \frac{8\pi G}{c^4}T_{uv}[/tex][/math] i understand that units of [math]g_{uv}=L^2[/math] and then [math]R=\Lambda=\frac{1}{L^2}[/math] ¿[math]R_{uv}[/math] is dimensional less?? [math]G=\frac{L^3}{T^2 M}[/math] and [math]\frac{G}{c^4}=\frac{T^2}{M}[/math] then ¿¿¿[math]T_{uv}=\frac{M}{T^2}[/math]????? Link to comment Share on other sites More sharing options...
Amr Morsi Posted April 29, 2010 Share Posted April 29, 2010 I think that the metric tensor is dimensionless and that the unit of the Ricci tensor is L^(-2). By the way, the unit of the stress-energy tensor is the unit of energy per volume. Link to comment Share on other sites More sharing options...
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