Jump to content

Why is called an open interval?

Featured Replies

It's all about sets;

 

As an example, consider the open interval (0, 1) consisting of all real numbers x with 0 < x < 1. Here, the topology is the usual topology on the real line. We can look at this in two ways. Since any point in the interval is different from 0 and 1, the distance from that point to the edge is always non-zero. Or equivalently, for any point in the interval we can move by a small enough amount in any direction without touching the edge and still be inside the set. Therefore, the interval (0, 1) is open. However, the interval (0, 1] consisting of all numbers x with 0 < x ≤ 1 is not open in the topology induced from the real line; if one takes x = 1 and moves an arbitrarily small amount in the positive direction, one will be outside of (0, 1'].

If you're asking about the reason behind the name, then I'm not sure, although I guess it's because it "goes on for ever" (ie.: has no minimum or maximum) therefore it's not "closed", but "open".

 

EDIT: Woops, didn't notice the post above :o)

  • Author
If you're asking about the reason behind the name, then I'm not sure, although I guess it's because it "goes on for ever" (ie.: has no minimum or maximum) therefore it's not "closed", but "open".

 

EDIT: Woops, didn't notice the post above :o)

 

See http://www.mathwords.com/o/open_interval.htm

 

But in this example it does. In this example the minimum is -2 and the maximum is 3. So why is it really called an open interval?

Here is what I mean:

 

As an example, consider the open interval (0, 1) consisting of all real numbers x with 0 < x < 1. Here, the topology is the usual topology on the real line. We can look at this in two ways. Since any point in the interval is different from 0 and 1, the distance from that point to the edge is always non-zero. Or equivalently, for any point in the interval we can move by a small enough amount in any direction without touching the edge and still be inside the set. Therefore, the interval (0, 1) is open. However, the interval (0, 1] consisting of all numbers x with 0 < x ≤ 1 is not open in the topology induced from the real line; if one takes x = 1 and moves an arbitrarily small amount in the positive direction, one will be outside of (0, 1'].

Archived

This topic is now archived and is closed to further replies.

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.