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Imaginary number paradox?


TheUnknown

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i = [math]\sqrt{-1}[/math]

i[math]^{4}[/math] = [math]\sqrt{-1}[/math][math]^{4}[/math] = 1

[math]\sqrt[4]{1}[/math] = i = 1

 

Therefore [math]\sqrt{-1}[/math] = 1, but that would mean that 1*1 = -1 Which is impossible.

 

How is this? Did I make a miscalculation? Or is this really a paradox?

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No paradox. You just did many things that are wrong. You ignored that [math]x^2=1[/math] has two solutions and [math]x^4=1[/math] has four and you assumed [math](ab)^c=a^c\,b^c[/math], which is valid only for real c and positive real a and b.

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I don't understand. All I did was take i, put it to the 4th power, and took that number and found its 4th root.

 

Shouldn't that, in the end, equal the same?

 

No. D H said what you did wrong in your calculation, which is why you got a clearly wrong answer. To start with, there is more than one root. 3^2 is 9, but the square root of 9 is either 3 or -3. Etc.

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Oh, I understand now. THANK YOU.

 

Phew, it was bugging me.

 

Let me see if I got this straight... the square root of -1, to the 4th power = 1. BUT taking the fourth root of 1 = 1, -1, i, or -i NOT both. So i doesn't necessarily = 1 or -1

 

What else could, to the fourth power, equal 1 other than 1 and -1? i seems to be both positive AND negative. (Which very well may be the point).

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