Jump to content

Newton's Method


Riogho

Recommended Posts

I'm using Newton's method to find the zero for this problem

 

[math]

\left( x^3 + 2x^2 - 4)^{\frac{1}{3}}

[/math]

 

Meh, I can't use latex.

 

The Cube root of X^3 + 2x^2 - 4

 

Anyways, I've ran it through a few times with my initial guess being 1.

 

The first itme I ran it through i got 2 as my answer, and then the second time my answer jumped over the actual root (which is 1.18 or something) to be .28942.... i checked my work and it's correct.

 

Why would it do that?

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.