Riogho Posted November 13, 2008 Share Posted November 13, 2008 I'm using Newton's method to find the zero for this problem [math] \left( x^3 + 2x^2 - 4)^{\frac{1}{3}} [/math] Meh, I can't use latex. The Cube root of X^3 + 2x^2 - 4 Anyways, I've ran it through a few times with my initial guess being 1. The first itme I ran it through i got 2 as my answer, and then the second time my answer jumped over the actual root (which is 1.18 or something) to be .28942.... i checked my work and it's correct. Why would it do that? Link to comment Share on other sites More sharing options...
D H Posted November 13, 2008 Share Posted November 13, 2008 Check your work again. Starting with an initial guess of 1, with Newton's method you should get the sequence 1, 1.125, 1.1230, 1.1303, 1.1304, ... Link to comment Share on other sites More sharing options...
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