Kyrisch 169 Posted March 31, 2009 Share Posted March 31, 2009 Just in case anyone's still curious: [hide] All the possible combinations of x + y + z = 13 and their products xyz: 1•1•11 = 11 1•2•10 = 20 1•3•9 = 27 1•4•8 = 32 1•5•7 = 35 1•6•6 = 36 2•2•9 = 36 2•3•8 = 48 2•4•7 = 56 2•5•6 = 42 3•3•7 = 63 3•4•6 = 72 3•5•5 = 75 4•4•5 = 80 All other combinations are commutatively equivalent. Looking back on the list, only one product appears twice. As such, the only way in which the student would need more information is if the number on the study were 36 because otherwise he would be able to figure out the ages based on the product. This is where the tricky part comes in; by saying that his eldest plays the violin, he implies that the ages are 2, 2, and 9 and not 1, 6, and 6 in which case he would have two 'eldest'.[/hide] Link to post Share on other sites

## Recommended Posts

## Create an account or sign in to comment

You need to be a member in order to leave a comment

## Create an account

Sign up for a new account in our community. It's easy!

Register a new account## Sign in

Already have an account? Sign in here.

Sign In Now