ajb Posted July 20, 2008 Share Posted July 20, 2008 [math]\rho^{i} =T^{0 i}/v^{i}[/math]? Not sure I understand what that means. The indices don't balance and I don't understand the meaning of division here. Anyway, am not going to be about for at lest a week. Sorry for the lack of the near future responses. Link to comment Share on other sites More sharing options...
Pete Posted July 20, 2008 Author Share Posted July 20, 2008 [math]\rho^{i} =T^{0 i}/v^{i}[/math]? Not sure I understand what that means. The indices don't balance and I don't understand the meaning of division here. T0i is the ith component of momentum density, vi is the ithe component of 3 velocity and [math]\rho^{i} =T^{0 i}/v^{i}[/math] is the ratio of the two. Anyway, am not going to be about for at lest a week. Sorry for the lack of the near future responses.Have fun! In the mean time I have to look into this more. It seems that I made an error above. The mass density as given by both Tolman and Rindler is [math]\rho = \gamma^2 (u) (\rho_0 + u^2t_0^{11}/c^4)[/math] which is not the ratio of momentum to speed as I believed. However the term proper mass densit does seem to have a unique meaning and thus is well defined. Pete Link to comment Share on other sites More sharing options...
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