Calculate the concentration of anions in a solution prepared by dissolving 0.605 g of cobalt(III) chloride in sufficient water to produce 350.0 mL of solution.

 

Anyones help would be greatly appreciated

molar mass CoCl3 = 165.28

 

Basically, divide the 3 Cl molar masses from the total: 106.35/165.28 = 0.643453533

Then, multiply that result by the mass of original substance: 0.605 x 0.643453533

= 0.389289387g (meaning that of the original 0.605g, 0.389... is Cl)

Then, to this result, divide it by the molar mass of 1 Cl molecule (35.45) = 0.010981364.

Then, you divide that number by the solution amount (0.35L) = 0.0314mol/L (to 3 significant figures)

 

hope it helps!

seems correct, the general formulas butterfly are, n= m/Mr and c= n/v