The letters A through M equal 202, hence the letters N to Z equal ???

 

Does anyone have a clue? I can't think of anything except assigning different integer values to vowels and consonants (which is a no go because then there's more than one solution), or similarly unsatisfying stuff.

each letter is worth 15.538461538461538461538461538462

 

That way, a-m =202, n-z = 202 also.

 

This is one possible answer which is not forbidden by the terms of the question.

Have you tried primes?

 

Let A=2, B=3, C=5, D=7, E=11, F=13, G=17 etc.

 

Add up only consonants.

It looks like it should be an evenly spaced series totalling 202, then totalling an even greater number past N, but I don't have time to figure it out right now.

 

No go, but I could think of a bunch of creative ways to make it work.

Have you tried primes?

 

Let A=2, B=3, C=5, D=7, E=11, F=13, G=17 etc.

 

Add up only consonants.

 

Ah, that's clever. It certainly works, though it does seem random. Still, kudos.