redfox Posted May 1, 2006 Share Posted May 1, 2006 Right, I've studied this for ages but my mind seems to be very slow...I can't figure it out! The set question goes as follows: A reaction between 1-Chloropropane (13.7g) and Sodium Cyanide (10.9g) gave, after purification, butanonitrile (CH3CH2 CH2CN) (6.65g). The first part of the problem is identifying the limiting reagent. This may be a bit long winded, but what I've come up with so far is... 1-Chloropropane = 78.536g mol-1 so 13.7/78.536 = 0.1744 in reaction. Sodium Cyanide = 49.01g mol-1 so 10.9/49.01 = .02224 in reaction. I am fairly sure the 1-Chloropropane is the limiting reagent, but am not certain it is. I'm not sure if the equation is finished...Also the next part of the question is calculation the theoretical yield of butanonitrile in grams but for that I need to know how many mols of each reagent there are. Believe me I've tried but am stuck now! Thanks in advance for any help offered! Link to comment Share on other sites More sharing options...
encipher Posted May 2, 2006 Share Posted May 2, 2006 Sodium Cyanide = 49.01g mol-1 so 10.9/49.01 = .02224 in reaction. 10.9 divided by 49.01 is not .02224 its .2184 Link to comment Share on other sites More sharing options...
redfox Posted May 2, 2006 Author Share Posted May 2, 2006 10.9 divided by 49.01 is not .02224 its .2184 No, it's 0.2224 Link to comment Share on other sites More sharing options...
redfox Posted May 2, 2006 Author Share Posted May 2, 2006 No worries, I think I have it now Link to comment Share on other sites More sharing options...
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