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Help with simple integral

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Was wondering if anyone could tell me how I'd go about integrating:

 

Int[(r(z))^2 dz] on the interval [1,h] where r(z) is an arbitrary function of z.

 

help is appreciated:)

Was wondering if anyone could tell me how I'd go about integrating:

 

Int[(r(z))^2 dz] on the interval [1' date=h] where r(z) is an arbitrary function of z.

 

help is appreciated:)

 

[math]\int^h_1{(r(z))^2}dz[/math]?

 

i'm not sure without knowing what z is.

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