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The integers 1,2,3,...,100 are written on the board. What is the smallest number of these integers that can be wiped off so that the product of the remaining integers ends in 2?

The product is even.

 

If it ends in 2 we're done, and the answer is 0.

If not, well, just think about how to divide out to make it end in 2.

well, for one thing there can be no multiples of five, because there would be no possibility of ending in 2...

 

There's probably an elegant way to figure this out but I don't see it yet

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